-4.9t^2+24+8=0

Solution for -4.9t^2+24+8=0 equation:

-4.9t^2+24+8=0

We add all the numbers together, and all the variables

-4.9t^2+32=0

a = -4.9; b = 0; c = +32;
Δ = b2-4ac
Δ = 02-4·(-4.9)·32
Δ = 627.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{627.2}}{2*-4.9}=\frac{0-\sqrt{627.2}}{-9.8}
=-\frac{\sqrt{}}{-9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{627.2}}{2*-4.9}=\frac{0+\sqrt{627.2}}{-9.8}
=\frac{\sqrt{}}{-9.8}
$